Se rezolva pas cu pas, pana ajungem doar la factori primi sub radical.
[tex]\begin{array}{rcl}\sqrt{468} &=& \sqrt{2\cdot 234} \\ &=& \sqrt{2\cdot 2\cdot 117} \\ &=& \sqrt{2^2 \cdot 3\cdot 39} \\ &=& \sqrt{2^2\cdot 3\cdot 3\cdot 13} \\ &=& \sqrt{2^2\cdot 3^2\cdot 13} \\ &=& \sqrt{2^2}\cdot \sqrt{3^2}\cdot \sqrt{13} \\ &=& 2\cdot 3\cdot \sqrt{13} \\ &=& \boxed{6\sqrt{13}} \end{array}[/tex]
