BE²=AE*EC9Teorema inaltimii in tr.dr BAC)=4√2*2√2=16⇒BE=√16=4
atunci Ariedreptunghi =2*ArieΔBAC=AC*BE=(4√2+2√2)*4=6√2 *4=24√2
BC²=EC*CA (teorema catetei in tr.dr BAC)=2√2*6√2=12*2=24⇒BC=√24=2√6
⇒AB=Arie dreptunghi:BC=24√2:(2√6)=12/√3=4√3
Perimetru dreptunghi =2(AB+BC)=2(4√3+2√6)=2*2√3(2+√2)=8√3+4√6