1 )
[tex]\it a~)~ \dfrac{77}{8}=77:8=9~rest~5=> 9 \dfrac{5}{8}[/tex]
[tex]\it b~)~ \dfrac{101}{3}=101:3=33~rest~2=> 33 \dfrac{2}{3}[/tex]
[tex]\it c~)~ \dfrac{978}{231}=978:231=4~rest~54=> 4 \dfrac{54}{231}[/tex]
2 )
[tex]\it \dfrac{2}{3} ; \dfrac{3}{4} ; \dfrac{5}{6} => 3= 3 ; 4={2}^{2} ; 6=2\cdot3 => 3\cdot {2}^{2} = 3\cdot4=12 => \dfrac{8}{12} ; \dfrac{9}{12} ; \dfrac{10}{12}[/tex]
3)
[tex]\it a= \dfrac{1}{2} + \dfrac{1}{4} + \dfrac{10}{8}=> a= \dfrac{4}{8} + \dfrac{2}{8} + \dfrac{10}{8} => a= \dfrac{16}{8} => a=2[/tex]
[tex]\it b= \dfrac{1}{2} + \dfrac{3}{5} + \dfrac{9}{10} => b= \dfrac{5}{10} + \dfrac{6}{10} + \dfrac{9}{10} => b= \dfrac{20}{10} => b=2[/tex]
a) Da , și a , și b sunt numere naturale (amândouă = 2)
[tex]\it a~(2) - \dfrac{1}{2} = \dfrac{4}{2} - \dfrac{1}{2} = \dfrac{3}{2}[/tex]
[tex]\it b~(2) - \dfrac{1}{3} = \dfrac{6}{3} - \dfrac{1}{3} = \dfrac{5}{3}[/tex]
[tex]\it \dfrac{3}{2} ; \dfrac{5}{3} => \dfrac{9}{6} ; \dfrac{10}{6} ; a - \dfrac{1}{2} < b - \dfrac{1}{3}[/tex]
4 )
[tex]\it \dfrac{2}{3} ; \dfrac{8}{9} ; \dfrac{26}{27} => \dfrac{18}{27} ; \dfrac{24}{27} ; \dfrac{26}{27} => ordine~crescatoare~= \dfrac{2}{3} ; \dfrac{8}{9} ; \dfrac{26}{27}[/tex]
