a+b+c=47
a=3b b=a/3
a=c-5 c=a+5
a+a/3+a+5=47
2a+a/3=42
6a+a=126
7a=126
a=126/7=18
b=18/3=6
c=18+5=23
in cazul in care suma celor 3 numerere este 57
a+b+c=57
a=3b b=a/3
a=c-5 c=a+5
a+a/3+a+5=57
2a+a/3=52
6a+a=156
7a=156
a=156/7
b=(156/7)/3=156/21=52/7
c=156/7+5=(156+35)/7=191/7
in acest caz numerele nu sunt naturale