HNO3
raport atomic=r.a.=1H:1N:3O=1:1:3
raport de masa =r. m.=AH:AN:3AO=1:14:3.16=1:14:48
Compozitia procentuala prin masa moleculara
MHNO3=1+14+3.16=63
63 g HNO3------1gH----14gN------48gO
100gHNO3--------xg--------yg-------zg
x=100:631,58 la suta H
y=100.14:63=22,22 la suta N
Z=100.48:63=76,19 la suta O
Daca in 63 g HNO3 se afla 1 g H atunci 10 g de H se afla in x g HNO3
63 gHNO3--------1gH
XgHNO3---------10 g H
X=63.10=630 gHNO3