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rezolvati aceste exercitii prin metoda mersului invers.


a+190+190:10=300




c-(600-315:9)=335


Răspuns :

a + 190 + 190 : 10 = 300
a + 190 +19 = 300
a + 219= 300
a = 300 - 219
a = 91

C-(600-315:9)=335
C-(600-35)=335
C-565=335
C=565+335
C=900


a+190+190:10=300
a+190+19=300
a+190=300-19
a+190=281
a=281-190
a=91
V 91+190+190:10=
91+190+19=
281+19=
300

c-(600-315:9)=335
c-(600-35)=335
c-565=335
c=335+565
c=900
V 900-(600-315:9)=
900-(600-35)=
900-565=
335