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Calculati procentul masic de carbon si hidrogen din compusul C10H20O

Răspuns :

MC10H20O=10•12+20•1+16=120+20+16=156g/mol
156gC10H20O...20gH...16gO
100gC10H20O...x gH...y gO
[tex]x = \frac{100 \times 20}{156} [/tex]
x=35,71%H
[tex]y = \frac{100 \times 16}{156} [/tex]
y=10,25%O