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Cine stie raspunsu.7-[100×52÷13-5×(3×120-2×a)]÷20=2 astept raspuns

Răspuns :

7 - [ 100 × 52 : 13 - 5 × ( 3 × 120 - 2 × a )] : 20 = 2
7 - [ 5.200 : 13 - 5 × ( 360 - 2 × a ) ] : 20 = 2
7 - [ 400 - 5 × ( 360 - 2 × a ] : 20 = 2
[ 400 - 5 × ( 360 - 2 × a )] : 20 = 7 - 2
[ 400 - 5 × ( 360 - 2 × a ) ] : 20 = 5
400 - 5 × ( 360 - 2 × a )] = 20 × 5
400 - 5 × ( 360 - 2 × a ) = 100
5 × ( 360 - 2 × a ) = 400 - 100
5 × ( 360 - 2 × a ) = 300
360 - 2 × a = 300 : 5
360 - 2 × a = 60
2 × a = 360 - 60
2 × a = 300
a = 300 : 2
a = 150

7 - [ 100 × 52 : 13 - 5 × ( 3 × 120 - 2 × a )] : 20 = 2
7 - [ 5.200 : 13 - 5 × ( 360 - 2 × a ) ] : 20 = 2
7 - [ 400 - 5 × ( 360 - 2 × a ] : 20 = 2
[ 400 - 5 × ( 360 - 2 × a )] : 20 = 7 - 2
[ 400 - 5 × ( 360 - 2 × a ) ] : 20 = 5
400 - 5 × ( 360 - 2 × a )] = 20 × 5
400 - 5 × ( 360 - 2 × a ) = 100
5 × ( 360 - 2 × a ) = 400 - 100
5 × ( 360 - 2 × a ) = 300
360 - 2 × a = 300 : 5
360 - 2 × a = 60
2 × a = 360 - 60
2 × a = 300
a = 300 : 2
a = 150

toata chestia aici e ordinea efectuarii operatiilor

mai intai rezolvi parantezele mari( drepte), apoi cele rotundee, inmultirile si impartirile, in ordine si apoi ultimele, adunarile si scaderile

sper ca te am ajutat!

coroana?