32) AB=10 cm
VO=12 cm
a) OM=AB/2=5
VM²=VO²+OM²
VM²=144+15
VM=√169
VM=13 cm
b) At=Al+Ab
At=Pb*Al/2=40*13/2 = 260
Ab=l^2=100 =) At= 360 m^2
c) In triunghiul VOC avem
VC²=VO²+OC²
VC²=144+50
VC²=194
VC=√194
in acelasi triunghi VC=√194 si VO=12 cm
teorema catetei =) VO²=VC*VT
144=√194*VT
VT=144/√194
