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scrie multimea divizorilor comuni ai nr si apoi precizeaza c.m.m.d.c. ai nr.:a)36 si 72;b)35si 45;c)30,36 si 54; d)40,60,120si 150
va rog pt coruana urgentt!


Răspuns :

a) D36={1,2,3,4,9,12,18,36}
D72={1,2,3,4,8,9,18,24,36,72}

[tex]36 = {2}^{2} \times {3}^{2} [/tex]
[tex]72 = {2}^{3} \times {3}^{2} [/tex]
[tex]c \: m \: m \: d \: c \: = {3}^{2} \times { 2 }^{2} = 9 \times 4 = 36[/tex]
b) D35={1,5,7,35}
D45={1,3,5,9,15,45}
[tex]35 = 7 \times 5[/tex]
[tex]45 = {3}^{2} \times 5[/tex]
[tex]c \: m \: m \: d \: c \: = 5[/tex]
c) D30={1,2,3,5,6,10,15,30}
D36={1,2,3,4,9,12,18,36}
D54={1,2,3,6,9,18,27,54}

[tex]30 = 2 \times 5 \times 3[/tex]
[tex]36 = {2}^{2} \times {3}^{2} [/tex]
[tex]54 = 2 \times {3}^{3} [/tex]
[tex]c \: m \: m \: d \: c = 2 \times 3 = 16[/tex]

d) D40={1,2,4,5,8,10,20,40}
D60={1,2,3,4,5,6,10,12,15,20,30,60}
D120={1,2,3,4,6,20,30,40,60,130}
D150={1,2,3,5, continua tu te rog }

[tex]40 = {2}^{3} \times 5[/tex]
[tex]60 = {2 }^{2} \times 5 \times 3[/tex]
[tex]120 = {2}^{3} \times 3 \times 5[/tex]
[tex]150 = 2 \times {5 \times 3}^{2} [/tex]
[tex]c \: m \: m \: d \: c \: = 2 \times 5 = 25[/tex]


Coroana pls !!