primul robinet:
10 ore......................100% (umble 100% din bazin)
6 ore........................ x %
_____________________ d.p.
10/6=100/x
=>10x=600 |:10
x=60%
deci, primul robinet umple in 6 ore 60% din bazin
inseamna ca al doilea robinet umple in 6 ore 100%-60%=40% din bazin
al doilea robinet:
6 ore...................40% (adica in 6 ore, al doilea robinet umple 40% din bazin)
y ore...................100%
___________________ d.p.
6/y=40/100
=>40y=600 |:40
y=15 (ore)
Raspuns: al doilea robinet umple bazinul in 15 ore