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Aflati numerele a , b , c astfel incat 2a + 3b + 4c =64 dau coroana

Răspuns :

2a+3b+4c=64 => a=2k|

                            b=3k|      din astea 3 rezulta ca 2a+3b+4c=64

                            c=4k|                                          2*2k+3*3k+4*4k=64

                                                                               4k+9k+16k=64

                                                                               29k=64

e ciudata problema.

imi pare rau doar pana aici am stiut sa fac