Ai aici rezolvarea. Am verificat in ambele sensuri: x1x2 sau x2x1.
Daca ai vreo intrebare nu ezita sa mi-o adresezi.
#include <iostream>
using namespace std;
int nr_cifre(int x)
{
if(x==0)
return 1;
int k=0;
while(x!=0)
{
k++;
x=x/10;
}
return k;
}
int oglindit(int x)
{
int aux=0;
while(x!=0)
{
aux=aux*10+x%10;
x=x/10;
}
return aux;
}
int main()
{
int x1, x2;
int k=0;
cout<<"x1=";
cin>>x1;
cout<<"x2=";
cin>>x2;
while(x1!=0 && x2!=0)
{
int cifre = nr_cifre(x2);
int cifre2 = nr_cifre(x1);
int aux1 = x1;
int aux2 = x2;
for(int i=0; i<cifre; i++)
aux1=aux1*10;
for(int i=0; i<cifre2; i++)
aux2=aux2*10;
aux1=aux1+x2;
aux2=aux2+x1;
if(aux1==oglindit(aux1) || aux2==oglindit(aux2))
k++;
cout<<"x1=";
cin>>x1;
cout<<"x2=";
cin>>x2;
}
cout<<"Perechi = "<<k<<endl;
return 0;
}
